If is a repeated root of ax^2+bx+c=0 then _ x (ax^2+bx+c) (x- )^2 is

JEE Advanced Mathematics question

If is a repeated root of then is

Answer: (B)

Since is a repeated (double) root, with . Hence

=· a → 1· a=a ,

because $a(x-α

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Question ID VK-109301