Let f(x) = 6 - 12x + 9x^2 - 2x^3, 1 x 4. Then the absolute maximum value of f(x) in the interval is

JEE Advanced Mathematics question

Let , . Then the absolute maximum value of in the interval is

Answer: (A)

f'(x) = -12 + 18x - = - - 3x + 2) = -6(x-1)(x-2).

For : (increasing); for : $f'(x) <

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Question ID VK-109431