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JEE Advanced Mathematics question

MathematicsFunctionJEE Advanced

The range of the function , , is

Answer: (A)

Solution

Break at and :

f(x) = Missing \end{cases}\begin{cases} -(2x+1) + 2(x-1) = -3, & x < -Missing argument for \tfrac\tfrac12 (2x+1) + 2(x-1) = 4x - 1, & -Missing argument for \tfrac\tfrac12 x < 1 (2x+1) - 2(x-1) = 3, & x 1

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Question ID VK-109434