Let f(x) be a function defined as below: f(x) = cases (x^2 - 3x), & x 0 6x + 5x^2, & x > 0. cases Then at x = 0, f(x)

JEE Advanced Mathematics question

Let be a function defined as below:

f(x) =

Then at ,

Answer: (B)

and , so is continuous at ((c) false).

For small (say ): (cosine of a small number is positive, ), so is

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Question ID VK-109436