JEE Advanced Mathematics question
Let for all real values of . Then
Answer: (A),(C)
Solution
h'(x) = f'(x) - 2f(x)f'(x) + 3\{f(x)\}^2 f'(x) = [1 - 2f(x) + 3\{f(x)\}^2]f'(x).
Complete the square:
- 2f + 1 = - 23 f + 19) + 23 = 3(f - + 23 > 0 .
So always has the same sign as .
See the full step-by-step solution
Create a free account to read the complete working (5 steps), and practise questions like this in a timed test.
Create a free account