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JEE Advanced Mathematics question

MathematicsApplication of DerivativesJEE Advanced

Let . Then

Answer: (B),(C),(D)

Solution

f'(x) = - 12x + 15 = - 4x + 5) = 3\{(x- + 1\} > 0 for all x .

So is strictly increasing on . - (a) ✗: is a cubic with positive leading coefficient, so as ; e.g. $f(-1) = -1 - 6 - 15 + 3 = -19 <

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Question ID VK-109453