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JEE Advanced Mathematics question

MathematicsDefinite IntegrationJEE Advanced

If then the smallest interval in which lies is

Answer: (C)

Solution

*Book's method.* Let . Then on , so is increasing and . Since is not constant,

0<I<Missing argument for \frac\frac19 (1-0)=Missing argument for \frac\frac19 .

*A sharper (equally simple) bound.*

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Question ID VK-109551