JEE Advanced Mathematics question
Let , and let be a nondecreasing continuous function in . Then has the
Answer: (A),(B)
Solution
nondecreasing on . Integrating over :
f(a)(b-a) f(x) dx f(b)(b-a)\ ⇒\ f(a)1{b-a} f(x) dx f(b),
with equality at either end when is constant. So the mean value has maximum and minimum : (a),
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