JEE Advanced Mathematics question

MathematicsDefinite IntegrationJEE Advanced

Let , and let be a nondecreasing continuous function in . Then has the

Answer: (A),(B)

Solution

nondecreasing on . Integrating over :

f(a)(b-a) f(x) dx f(b)(b-a)\ ⇒\ f(a)Missing argument for \frac\frac1{b-a} f(x) dx f(b),

with equality at either end when is constant. So the mean value has maximum and minimum : (a),

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Question ID VK-109575