The general solution of the equation (1+y^2)+ (x-e^ ^ -1 y ) dy dx =0 is

JEE Advanced Mathematics question

The general solution of the equation is

Answer: (A)

Treat as a function of : , i.e.

+ x=,

linear in . e^{\int\frac{dy}{1+y^2}}\tan$^{-

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Question ID VK-109605