The differential equation (x) ,dy=y '(x)-y ,dx is changed in the form df(x,y)=0. Then f(x,y) is

JEE Advanced Mathematics question

The differential equation is changed in the form . Then is

Answer: (B)

Expand: \phi\,dy=y\phi'\,dx-y^2dx\Rightarrow y\phi'(x)\,dx-\phi(x)\,dy=y^2dx. Divide by :

=dx .

The left side is exactly

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Question ID VK-109608