Let f(x) = 1 - (1-x)^2, x 1. The number of solutions of the equation f f(x) = x is

JEE Advanced Mathematics question

Let . The number of solutions of the equation is

Answer: (B)

. Since , maps into , so is defined for all .

. Setting this equal to :

x[(2--2x+2) - 1] = 0 ⇒ x[- + - 6x +

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Question ID VK-109965