JEE Advanced Mathematics question
The value of is equal to
Answer: (A)
Solution
Write and apply Pascal's rule repeatedly:
{}^{n+1}+{}^{n+1}={}^{n+2}, {}^{n+2}+{}^{n+2}={}^{n+3},\ ,\ {}^{2n}+{}^{2n}={}^{2n+1} .
So the sum telescopes to .
*Book's method:* ${}^{n+
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