Let f(x) = 1 + | x|. Then

JEE Advanced Mathematics question

Let . Then

(A) is continuous nowhere
(B) is continuous everywhereCorrect
(C) is differentiable nowhere
(D) does not existCorrect

Answer: (B),(D)

Solution

is continuous everywhere and differentiable except at ; is continuous and differentiable everywhere. So (and ) is continuous everywhere, and differentiable except where with a sign change,

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Question ID VK-110473