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JEE Advanced Mathematics question

MathematicsSolution of TrianglesJEE Advanced

Not in JEE syllabus

The internal bisector of the angle of the meets at . A line drawn through perpendicular to intersects the side at and the side produced at . Then

Answer: (A),(B),(C),(D)

Solution

*(Figure: triangle ABC with bisector AD meeting BC at D; the line through D perpendicular to AD meets AC at E and BA extended beyond B at F.)*

- (c) ✅ :

Missing argument for \tfrac\tfrac12 bc A = Missing argument for \tfrac\tfrac12 c· ADMissing argument for \tfrac\tfrac A2 + Missing argument for \tfrac\tfrac12 b· ADMissing argument for \tfrac\tfrac A2 ⇒ AD = Missing argument for \frac\frac{bc

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Question ID VK-110619