JEE Main 2015 Chemistry question
The following reaction is performed at 298 K. . The standard free energy of the formation of NO(g) is 86.6 kJ at 298 K. What is the standard free energy of the formation of (g) at 298 K?
Answer: (1)
Solution
For the reaction, \Delta G^\circ = 2\Delta_fG^\circ(NO_2) - 2\Delta_fG^\circ(NO) = -RT\ln K_P (oxygen is an element, so its
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