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JEE Main 2015 Chemistry question

ChemistrySolutionsJEE Main 2015

The vapour pressure of acetone at 20 °C is 185 torr. When 1.2 g of a non-volatile substance was dissolved in 100 g of acetone at 20 °C, its vapour pressure was 183 torr. The molar mass of the substance is:

Answer: (3)

Solution

The relative lowering of vapour pressure equals the mole fraction of solute, which for a dilute solution is : $ =

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Question ID VK-115176