The normal to the curve x^2 + 2xy - 3y^2 = 0, at (1, 1)

JEE Main 2015 Mathematics question

The normal to the curve , at (1, 1)

Answer: (1)

Differentiating, , which at (1, 1) gives ; so the normal has slope −1 and is . The curve factorises as .

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Question ID VK-115214