JEE Main 2015 Physics question
Diameter of a steel ball is measured using a Vernier calipers which has divisions of 0.1 cm on its main scale (MS) and 10 divisions of its Vernier scale (VS) match 9 divisions on the main scale. Three such measurements for a ball are given as: S.No. 1: MS = 0.5 cm, VS divisions = 8; S.No. 2: MS = 0.5 cm, VS divisions = 4; S.No. 3: MS = 0.5 cm, VS divisions = 6. If the zero error is cm, then mean corrected diameter is:
Answer: (3)
Solution
Since 10 VSD = 9 MSD, the least count is cm. The three readings are cm, cm and cm, whose mean is
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account