JEE Main 2015 Physics question
A cylindrical block of wood (density kg m), of base area 30 cm and height 54 cm, floats in a liquid of density 900 kg m. The block is depressed slightly and then released. The time period of the resulting oscillations of the block would be equal to that of a simple pendulum of length (nearly):
Answer: (3)
Solution
If the block is pushed down a further distance , the extra buoyant force is and acts as a restoring force, so and . Hence . Comparing with the pendulum formula $T =
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