JEE Main 2015 Physics question
Not in JEE Advanced syllabus
A short bar magnet is placed in the magnetic meridian of the earth with North Pole pointing north. Neutral points are found at a distance of cm from the magnet on the East-West line, drawn through the middle point of the magnet. The magnetic moment of the magnet in Am is close to: (Given in SI units and = Horizontal component of earth's magnetic field Tesla.)
Solution
With the north pole pointing north, the magnet's field *opposes* the earth's horizontal field along the equatorial (East-West) line through its centre, so the neutral points lie there. On the equatorial line the magnet's field is , and at a neutral point this equals .
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