JEE Main 2015 Physics question
In a Young's double slit experiment with light of wavelength , the separation of slits is and distance of screen is such that . If the Fringe width is , the distance from point of maximum intensity to the point where intensity falls to half of the maximum intensity on either side is:
Answer: (1)
Solution
The intensity in a two-slit pattern is , where is the phase difference. Setting gives , so and . The corresponding path difference is \frac{λ}{2π}$φ =
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