JEE Main 2015 Mathematics question
If the two roots of the equation, are real and distinct, then the set of all values of is equal to
Answer: (2)
Solution
The key is the factorisation , obtained by writing . Substituting and taking out the common factor,
+x+1)[(a--x+1) + (a++x+1)] = 0.
Since has discriminant $-3
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