JEE Main 2015 Mathematics question

MathematicsApplication of DerivativesJEE Main 2015

The equation of a normal to the curve, at , is:

Answer: (4)

Solution

At the equation gives , so the point of interest is . Differentiate implicitly with respect to :

y = (Missing argument for \frac\frac3+y) + x(Missing argument for \frac\frac3+y).

Evaluating at , the last term vanishes because , leaving

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Question ID VK-115393