The solution of the differential equation y ,dx - (x+2y^2 )dy = 0 is x = f(y). If f(-1) = 1, then f(1) is equal to

JEE Main 2015 Mathematics question

The solution of the differential equation is . If , then is equal to

Answer: (2)

The equation is not linear in , but it *is* linear in regarded as a function of . Rearranging,

y - x = ⇒ - xy = 2y.

The integrating factor is , and

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Question ID VK-115398