JEE Main 2016 Physics question
Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to and , respectively. At time one particle has displacement while the other one has displacement and they are moving towards each other. If they cross each other at time , then is:
Answer: (4)
Solution
Write both motions with the same . The first particle starts at the extreme and must move towards the other (i.e. in the direction), so
= Aω t.
The second starts at moving in the direction. Writing , the initial position gives
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