JEE Main 2016 Mathematics question

MathematicsVector AlgebraJEE Main 2016

The shortest distance between the lines and , lies in the interval:

Answer: (2)

Solution

The first line passes through the origin with direction ; the second passes through with direction . Their cross product is

Missing argument for \vec\vec ×Missing argument for \vec\vec = (2·4-1·8,\ 1·(-1)-2·4,\ 2·8-2·(-1)) = (0, -9, 18),

with magnitude $\

See the full step-by-step solution

Create a free account to read the complete working (5 steps), and practise questions like this in a timed test.

Create a free account

Question ID VK-115581