JEE Main 2017 Physics question
A diverging lens with magnitude of focal length cm is placed at a distance of cm from a converging lens of magnitude of focal length cm. A beam of parallel light falls on the diverging lens. The final image formed is:
Answer: (2)
Solution
Take light travelling left to right and use with the Cartesian sign convention. **Diverging lens** ( cm): parallel light means , so
1{} = 1{} = -1{25} = -25\ cm,
a virtual image cm to the left of the
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