JEE Main 2017 Physics question
The maximum velocity of the photoelectrons emitted from the surface is when light of frequency falls on a metal surface. If the incident frequency is increased to , the maximum velocity of the ejected photoelectrons will be:
Answer: (1)
Solution
Einstein's photoelectric equation gives, for the first case,
12 = hn - φ,
where is the work function. For the tripled frequency,
12 mv'^2 = 3hn - φ.
Now rewrite the second in terms of the first:
3hn - φ = 3(hn - φ) + 2φ = 3( + 2φ.
Since , the right-hand
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