JEE Main 2017 Physics question

PhysicsNucleiJEE Main 2017

Two deuterons undergo nuclear fusion to form a Helium nucleus. The energy released in this process is (given binding energy per nucleon for deuteron MeV and for helium MeV):

Answer: (1)

Solution

The reaction is

^\mathrm H + {}^\mathrm H He.

The energy released equals the increase in total binding energy, since a more tightly bound product releases the difference. **Reactants:** each deuteron has nucleons at MeV per nucleon, so MeV in

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Question ID VK-115790