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JEE Main 2017 Chemistry question

ChemistryChemical KineticsJEE Main 2017

The rate of a reaction A doubles on increasing the temperature from to K. By how much, the temperature of reaction B should be increased from K so that rate doubles if activation energy of the reaction B is twice to that of reaction A.

Answer: (1)

Solution

The Arrhenius equation in two-temperature form reads

= ( - ).

**Reaction A:** doubling from K to K,

2 = (Missing argument for \frac\frac1{300} - Missing argument for \frac\frac1{310}) = ยท = 9300 R

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Question ID VK-115813