The locus of the point of intersection of the straight lines, tx - 2y - 3t = 0 and x - 2ty + 3 = 0 (t R), is:

JEE Main 2017 Mathematics question

The locus of the point of intersection of the straight lines, and , is:

Answer: (1)

Eliminate the parameter . From the first equation, , so

t = (x3).

Substituting into the second equation,

x - 2y· + 3 = 0 (x+3)(x-3) = - = 9.

Dividing by ,

- = 1,

a **hyp

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Question ID VK-115830