The tangent at the point (2,-2) to the curve, x^2y^2 - 2x = 4(1-y) does not pass through the point:

JEE Main 2017 Mathematics question

The tangent at the point to the curve, does not pass through the point:

Answer: (1)

Differentiate the curve implicitly:

+ - 2 = -4.

Substitute : the first term is and the coefficient of on the left is , so

16 - 16 - 2 = -4 14 = 12

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Question ID VK-115844