NEET Biology question

A woman with two genes for haemophilia and one gene for colour blindness, both present together on one of her 'X' chromosomes, marries a normal man. How will the progeny be?

(A)50% haemophilic and colour-blind sons; 50% normal sonsCorrect
(B)50% haemophilic daughters (carrier) and 50% colour-blind daughters (carrier)
(C)All sons and daughters haemophilic and colour-blind
(D)Haemophilic and colour-blind daughters

Answer: (A)

Solution

The woman's genotype is (one X chromosome carrying both the haemophilia allele and the colour-blindness allele , linked together; the other X is normal). Crossed with a normal man (): sons receive the father's Y plus either the mother's (50%, giving — affected by both

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-120229