NEET Biology question
If frequency, of ‘A’ allele is 0.4 than, find out the frequency of ‘B’ allele and heterozygous genotype in a random mating population at equilibria
Answer: (C)
Solution
HW Principle = p + q =1 *p*2+2*pq*+*q*2 = 1 Here, p = A and q is = B Allele frequency of B = 1-0.4 = 0.6
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