JEE Main Chemistry question
The equivalent weight of a solid element is found to be 9. If the specific heat of this element is 1.05 J gK (i.e. 0.25 cal gK), then its atomic weight is
Answer: (D)
Solution
By Dulong-Petit's law, atomic weight specific heat J molK (equivalently cal molK). Using the specific heat in J gK: valency \dfrac${\text{atomic
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