The molecular weight of air will be (the components of air given as N_2 - 78%, O_2 - 21%, Ar - 0.9% and CO_2 - 0.1%)

JEE Main Chemistry question

The molecular weight of air will be (the components of air given as - 78%, - 21%, - 0.9% and - 0.1%)

Answer: (C)

Weighted average molar mass $=28×0.78+32×0.21+39.9×0.009+44×0.001=21.84+6.72+0.359+0.044=28

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Question ID VK-130581