JEE Main Chemistry question
100 mL of 20.8% BaCl solution and 50 mL of 9.8% HSO solution will form BaSO. Solution (Ba = 137, Cl = 35.5, S = 32, H = 1, O = 16):
Answer: (B)
Solution
100 mL of 20.8% BaCl contains 20.8 g BaCl (), i.e. 0.1 mol. 50 mL of 9.8% HSO contains 4.9 g (), i.e.
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