JEE Main Chemistry question
A 200 mL solution of I is divided into two unequal parts. Part I reacts with hypo solution in acidic medium and requires 8 mL of 2 M hypo solution for complete neutralisation. Part II was added to 300 mL of 0.1 M NaOH solution. Residual base required 30 mL of 0.1 M HSO solution for complete neutralisation. Calculate the value of 20 times the initial concentration of I.
Answer: (B)
Solution
Part I: mmol hypo ; since , mmol I. Part II: ; excess NaOH
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