JEE Main Chemistry question

Chemistry Solutions JEE Main

The amount of oxalic acid (hydrated) required to prepare 500 mL of its 0.1 N solution is:

(A)0.315 g
(B)6.3 g
(C)3.15 gCorrect
(D)63.0 g

Answer: (C)

Solution

Eq. wt. oxalic acid dihydrate . Mass g.

Question ID VK-131056