JEE Main Chemistry question
Pressure exerted by 1 mole of methane in a container at using van der Waals' equation is (Given, , ) **[Pb CET 2010]**
Answer: (A)
Solution
\dfrac{nRT}{V-nb}\dfrac{an^2}{V^2}\dfrac{1×0.0821×300}{0.25-0.0428}\dfrac{2.253×1}{0.25^2}$
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