H _2 O (l) 1 atm H _2 O (g), H_ vap = 10 kcal mol ^ -1 . If pressure is increased

JEE Main Chemistry question

H_2O(l) H_2O(g),\ Δ = 10\ kcal mol^{-1}.

If pressure is increased

(A)Steam is liquefied
(B)Boiling point of is elevated
(C)Both (a) and (b)Correct
(D)None of these

Answer: (C)

Solution

By Le Chatelier's principle, raising the pressure on this equilibrium shifts it toward the side of smaller volume, i.e. toward the liquid, so some steam condenses. Separately, boiling requires the vapour pressure to equal the external

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Question ID VK-134121