12I_2(g) + 12Cl_2(g) ICl(g) (using the data, _ diss H^ _ Cl_2 = 240 kJ mol^ -1 , _ diss H^ _ I_2 = 151.0 kJ...

Question

12I_2(g) + 12Cl_2(g) ICl(g) (using the data, _ diss H^ _ Cl_2 = 240 kJ mol^ -1 , _ diss H^ _ I_2 = 151.0 kJ mol^ -1 , sublimation enthalpy of I_2(s) = 62.76 kJ mol^ -1 , and bond dissociation enthalpy of ICl = 211.3 kJ mol^ -1 ) Given that the standard states for iodine and chlorine are I_2(s) and Cl_2(g), the standard enthalpy of formation of ICl(g) is **[AIEEE 2006]**

Accepted Answer

(C)

JEE Main Chemistry question

Solution

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