JEE Main Chemistry question
If at 298 K the bond energies of C-H, C-C, C=C and H-H bonds are respectively 414, 347, 615 and 435 , the value of enthalpy change for the reaction, at 298 K will be
Answer: (D)
Solution
$Δ H = [4 BE(C{-}H)+BE(C{=}C)+BE(H{-}H)] - [6 BE(C{-}H)+BE(C{-}C)] =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account