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JEE Main Chemistry question

ChemistryThermodynamicsJEE Main

48 g of on complete combustion evolves 1584 kJ of heat. The standard heat of formation of gaseous carbon is 725 kJ/mol. The energies required for the process (i) (ii) are

Answer: (C)

Solution

Combustion of 48 g (4 mol) diamond releases 1584 kJ, so . Using and : \Delta H(C(gas)+O_2\rightarrow CO_2) = -393.5-725 = -1118.5\ kJ/mol. For graphite: $Δ

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Question ID VK-134922