JEE Main Chemistry question
The bond energies of H-H, Br-Br and H-Br are 433, 192 and respectively. The for the reaction is
Answer: (D)
Solution
\Delta H^\circ = [BE(H{-}H)+BE(Br{-}Br)]-2\times BE(H{-}Br) = (433+192)-2(364) = 625-728 = -103\ kJ.
The bond energies of H-H, Br-Br and H-Br are 433, 192 and respectively. The for the reaction is
\Delta H^\circ = [BE(H{-}H)+BE(Br{-}Br)]-2\times BE(H{-}Br) = (433+192)-2(364) = 625-728 = -103\ kJ.