JEE Main Chemistry question
If CH_3COOH+OH^- = CH_3COO^-+H_2O+q_1 and , then the enthalpy change for the reaction CH_3COOH = CH_3COO^-+H^+ is equal to
Answer: (C)
Solution
The given equations mean (for CH_3COOH+OH^-\rightarrow CH_3COO^-+H_2O) and (for ). Subtracting, H_1$-Δ
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