JEE Main Chemistry question
Two moles of CO and one mole of react in a closed container of volume one litre to form 2 moles of at a constant temperature. These gases deviate appreciably from ideal behaviour. The value of enthalpy change is . If the pressure in the container changes from 70 to 50 atm, then what is the absolute value of in kJ?
Answer: 58
Solution
Since volume is fixed (closed container), V(P_2P_1)$=1\ L×(50-70)\ atm=-20\ L· atm=-20×0.101325=-2.0265\
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