The equilibrium constant, K for the reaction 2HI(g) H_2(g)+I_2(g) at room temperature is 2.85 and that at 698 K, it is 1.4 10^ -2 . This implies that

JEE Main Chemistry question

The equilibrium constant, for the reaction at room temperature is 2.85 and that at 698 K, it is . This implies that

(A)HI is resonance stabilised
(B)HI is exothermic compound
(C)HI is stable at room temperature
(D)HI is less stable than and Correct

Answer: (D)

Solution

for the decomposition drops sharply with increasing temperature, meaning the decomposition is exothermic and HI's formation from is actually endothermic (consistent with

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Question ID VK-135827