JEE Main Chemistry question
Calculate the pH at the equivalence point when a solution of 10⁻⁶ M CH₃COOH is titrated with a solution of 10⁻⁶ M NaOH. Kₐ for the acid = 2×10⁻⁵ (pKₐ = 4.7). (Answer given in whole number)
Answer: 7
Solution
At the equivalence point, acetate concentration is extremely dilute (~5×10⁻⁷ M). [OH⁻] from hydrolysis = √(Kb·C) = √(5×10⁻¹⁰ × 5×10⁻⁷) ≈
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