JEE Main Chemistry question
For a reversible reaction, the rate constant for the forward reaction is 2.38×10⁻⁴ and for the backward reaction is 8.15×10⁻⁵. The Kc for the reaction is:
Answer: (B)
Solution
Kc = kf/kr = 2.38×10⁻⁴/8.15×10⁻⁵ = 2.92.
For a reversible reaction, the rate constant for the forward reaction is 2.38×10⁻⁴ and for the backward reaction is 8.15×10⁻⁵. The Kc for the reaction is:
Kc = kf/kr = 2.38×10⁻⁴/8.15×10⁻⁵ = 2.92.